given,
kc = 1.6 × 10^-4
now,
pkc = -log(kc)
pKc = -log(1.6×10^-4)
= 3.79588
in 2 significant figures
pkc = 3.8
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(a)
Write the expression for the equilibrium constant (Kc)
(b)
Find Kc, when the equilibrium concentrations for NOBr, NO and Br2
are 0.46 M, 0.1 M and 0.3 M respectively. Report to 3 Significant
figures.
(c)
Find Kp for the abovementioned reaction at 25°C. (R=0.082 L.
atm/mole.K)
(d)
Find Kc, for this reaction: NO(g) + 1/2 Br2 (g) <-> NOBr
(g)
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At a certain temperature the equilibrium constant, Kc, equals 0.11 for the reaction: 2 ICl(g) ⇌ I2(g) + Cl2(g). What is the equilibrium concentration of Cl2 if 2.68 mol of I2 and 2.68 mol of Cl2 are initially mixed in a 3.0-L flask? *Please report 3 significant figures. Numbers only, No unit. No scientific notation.