Question

I need help finding calculated pH for part IV and part V please!

su 13.21 Part IV: Dilution of Buffered and Unbuffered Solutions Calculated pH | Calculated ApH Observed pH Observed ApH Number Preparation 15 ml. HC H3O2(aq) 15 ml NaC,HO2(aq) 5 ml Solution 1 25 mL H20 5 ml Solution 2 25 ml H20 4 30 mL HC H2O2(aq) 5 ml Solution 4 25 ml H2O 5 ml Solution 5 25 ml. H2O 4.10 4.10 4.10 06 2. 37 2.168 Part V: Adding Strong Acid or Base to Unbuffered Solutions Concentration of HCI .0 M Preparation Calculated pH Calculated ApH Observed pH Observed pH Beaker 1 30 ml H2O (6.78 30 ml H20 2 ml. -1.0 MHCI 1.39 30 ml. H2O 2 ml. -1.0 M NaOH 30 ml. HC H2O2(aq) 30 ml NaC2H3O2(aq) 30 ml buffer 2 ml -1.0 MHCI 30 ml buffer 12 ml -1.0 M NaOH 12.39 4.23 410 4.42

pKa of acetic acid= 4.744

Answer 1

pka Acetic CH3 cool CH3cOo Na Acid 24.74 0.5M 0.5M PH Part IV (1) 15mi Acom 15 ml ACONA soj pH = 4.74 upon ditution the Relative Raños of salt and Aid | Again H (2) 5 mi son 1 pH = 4.74 I won't change 25 mi H2O Again PH= 4.74 5 ml solna 20 25ml (3) No change in the raños of salt and Acid won't change H2O (4) 30 ml of AcOH PATH te 66 l pH - pka - Loge c=0.5 / pH = 2.52 ht= kaxe

(4) Som Acolt 30ml Acona ph, 4.74 | As Balt] f(Aud] =1 (5) 30 ml buffer 2ml, 1.0M HO upon addition of Hel (H+) CH3600 +ht ² CH3cOoh more Acetic Acid will be produced Log (Salt / Acid) Lo soj pH reduces Hei = [ht] = 1x2 = 0.0625 0.25 -00625 0.25 +0.0625 6) 30 ml buffer pH= pka & Log 0.25 4.747 Log 0.1875 2ml, lom NaOH 0. 3125 4.51 » phapka + Log 0.25 +00625 ๖) 004 0.25 to 0625 pH = 4.96