QUESTION 15 At 25 °C the solubility of barium fluoride is 7.52 x 10 mol/L Calculate...

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science chemistry

Answer 1

Answer #1

(solubility equiliboium - Belan Cs) — Bel+caq) + 2F caq) Solubility - produet constant expression:- Ksp = [Bapt] [F]2 Bafe -

Answer 2

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