questions 1 & 2 1. The following reaction occurs at 419 K. kpke (RT 3X(g) +...

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Question

questions 1 & 2
1. The following reaction occurs at 419 K. kpke (RT 3X(g) + 2Y(g) = 2(g) Kc = 0.0758 M-2 R3.0821 Lam Calculate Ke 2-12+2) = -

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Answer 1

Answer #1

II 3X (g) + 2Y (g) 2 269) Ke= 0.0758 m2 кр = k (ет, а Ang = change in gaseous number of roles. Dug = (Eng) products - (Eng) R

Answer 2

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