Question

1) Use both the ionic and covalent counting systems as was done in the examples in class to give electron counts for the metal and each type of ligand. Use these to determine the total electron count for these organometallic compounds (watch for oxidation state of cationic complexes! Also, not all are 18 e): HC Fe.co

Answer 1

I compound counting Method Covalent Jonic → 2x B8 2x(26) Brx2 By RxGH → 2X (6e |2x G H 5 Zo= [kr] 42²55² 16e- N-CSHS is what C Hs exist as. axle- 2xse- 16e D. 10 a CH. re do YO Fe [A] 3 d6 4² CGHS n3-65H5 Feet - CH₃ CH2 → 2xco Cg H5 bé-Fe - 26-2400 - 2x 26- CH₂ CH₂ - be 15-cche Toe 8e- 2x20 le- 5 e- Toe- Rb + Phyp BbPPh ₂ Se Bh 2e-Ico 26 H 2x21 - 2x PPha qe 2e- le- 2x2e- Php to 2x PPh 16e- de n H Bipheryl be - Biphenyl be - Ru be- - se Ruzt Ru- 2e-la -ce w le- H NM len > 46- en WH2 Prethylene diamine) 18 e- 4e- 19- -le 18c-

8- Co 3620) 3460 on coco no q co 360 G- 3é 3x de lee- 18e- (dut belid bet loe- 3x F- 3E lye - Pd - [ko]4d10 0553 le- Horro Te- L₂ - Lot