Homework Answers
Given reaction:
4 Fuel + 9 O2 ------> 8 CO2 + 10 H2O + 2 N2
We know that, Enthalpy of reaction is given by:
ΔHorxn = Σ ΔHof (products) - Σ ΔHof (reactants)
ΔHorxn = [8 ΔHof (CO2) + 10 ΔHof (H2O) + 2 ΔHof (N2)] - [4 ΔHof (fuel)]
Therefore:
4 ΔHof (fuel) = [8 ΔHof (CO2) + 10 ΔHof (H2O) + 2 ΔHof (N2)] - ΔHorxn
4 ΔHof (fuel) = [8* -393.5 + 10* -285.8 + 0] - [-3857] kJ/mol
4 ΔHof (fuel) = -2149 kJ/mol
ΔHof (fuel) = (-2149 kJ/mol) / (4)
ΔHof (fuel) = -537.2 kJ/mol -----------------(ANSWER)
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The combustion of lauric acid is given by the following thermochemcial equation: CH3(CH2)10COOH(s) + 18 O2(g)...
The combustion of lauric acid is given by the following
thermochemcial equation: CH3(CH2)10COOH(s) + 18 O2(g) → 12 H2O(l) +
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for CO2(g) and H2O(l) calculate the heat of formation (△fH) of
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help asap 3. Calculate the standard enthalpy change, Hº, for the following reaction using standard enthalpies of for...
help asap
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The combustion of lauric acid is given by the following
thermochemcial equation: CH3(CH2)10COOH(s) + 18 O2(g) → 12 H2O(l) +
12 CO2(g) Hcomb is −7377 kJ mol−1 Using the heats of formation
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help asap
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