Question

Gd 15E " Ne Pu Am Cm Bk Cf Es Fm Md No What is the energy of the electron in a helium ion with a charge of +1 in an orbit with a value of n = 42 • Use k = 2.179 x 10-18 J. . Report your answer with three significant figures. Provide your answer below: FEEDBACK MORE INSTRUCTION SUBMIT Content attribution earch

Answer 1

Answer:

Step 1: Explanation

The expression for the energy of an electron in an excited state is given by :

En = -2.178 × 10-18 J × ( Z2 / n2 )

Where,

Z = atomic number

Step 2: Calculation

Given,

n = 4

Z = 2 [ Note : Given, helium which means atomic number = 2 ]

on substituting the value

En = -2.179 × 10-18 J × ( Z2 / n2 )

=> E4 = -2.179 × 10-18 J × ( 22 / 42 )

=> E4 = -5.45 × 10-19 J [ Note : where, J = joules ]

Hence, The electron will have energy = -5.45 × 10-19 J