Question

The solubility of Ag2CrO4 is measured and found to be 4.24×10-2 g/L. Use this information to calculate a Ksp value for silver chromate. Ksp =

Answer 1

The dissociation of Ag, CrOq in solution is given by AQ 046 = 2 Ag+ (0q) + Groot loq) where s' is the solubility in mol/L Ksp = [Ag+] ² [ Cropen] Ksp : (25)*(5) (kap = 45²

Given I solubility in g/ha 4.24 x 102 g/L Molar mass of Ag Croq = 332 g/mol Solubility in mol/La solubility in g/L Molar mass s = 4.24 x 10-2 332 1.27 x 10-4 moll 8 =

Putting the value of 's in the expression "lesp = 453 Icsp = (1.27X10-4)3 x 4 | Ksp = 8. 19 x10-12