Question

Lab 7: Question 8 Homework – Unanswered Why would an acid-base extraction procedure be inefficient in separating 1-111? LOHCOOH M 1,0 r.com O A Compounds II and III are water soluble in their neutral forms The pka values of ll and Ill are not different enough to enable selective deprotonation based on base strength Ос The deprotonated form of Il that is isolated after extraction is too stable to be protonated to recover neutral Il

Answer 1

The answer is A.

Explanation:

Butyric acid and propanol in their neutral form(without protons) are soluble in water. This will favor the formation of products(neutral ones) which result in the ionization and extraction of the two compounds at the same time. This will make difficult to etract both. So neutral forms which is soluble in water is responsible for the difficulty in acid base extraction of i & ii.

Their pKa value are to diiferent enough for separation. pKa(butyric acid) = 4.82 and pKa(propanol) = 16

So this is not tge reason.

Deprotonated form of ii is not thqt stable enough to make it recovery problems. So this too is not the reason.