Question

anyone know if im doing this right?

314 D. (11 points) Strictly speaking. gallic acid is a diprotic acid in water: www.frontissimogaticies/103389/chem 2019. full H.C.H.O.(a) H(aq) + HC,H,O, Tag) K. - 4.57 10 - HCLO (aq) + H'(aq) + C3H4O? (aq) Ka-3,16 = 10* Determine K for the following chemical equations. Be sure to show how you determined the equilibrium constants from the above information. 1. H.C.H.O.(aq) + 2H(aq) + CH.03(aq) This equation is just aelding the 2 equations above. When you add them, they are multiplied in the Keguation. So I multiply Kai by Kaza (4.57x10-3) x (3.16*10-4 - 1.44 x 10- 2. 2HCHOs (aq) = H.CH,Os(aq) + CH.O(g) This equation is just another derivation of the original 2 equations. It is flipped therefore I would take the reciprocal of the Kai are Kaz 3.168107 -6.91810-7 = Kof 4,57x10-3 3. 3HC;HOs (aq) + H'(ag) = 2H2C;HOs(aq) + C;H03? (aq)

Answer 1

The way you are doing it is correct there is one more way of doing this question i have also mentioned that.

The way you are doing it is correct You can also do it by writing the expression for Ka.. Ис, ило, — натиси, о-) Пka. – [н'] Інс, ног) - .50 x )о Гис, но Ас, но, р.) = " - сно, а K, - [н'] [с, но*) - 3.4 xlo - 9 ГИС, Н40;) не 40х «р тэн ус, дуоҳ ва » Кар - [н'] 2 [c.140.4] . ka xko, En , но) - ). 44 x lo". 2) дис, ило, висно сно К - (H,с, но и40) Lic, H407) = 3 1 6x lo“ 2 6 41 x |о- Ка, KOT 4. 5nҳlo - 3

3) зис, но и 2м , че ГИс, ио ј3 СА) — Каз". Сарсено 2-3 Сис, нҳо, Ка, е си с нҳо, 13 сн: Сиси, о 2 (3.16 xla ) - 51l xlo 21 ( Ч, 50 х 10-3) 2-