Question

1. Calculate the theoretical yield of $Znl_{2}$ based on Equation 1 and the initial mass of the limiting reagent.

Equation (1) Zn(s) + I2(s) → ZnI2(s)

Mass of Zinc 0.6404 g

Mass of Iodine 0.6544 g

Mass of dried Zinc Iodide (Experimental Yield) 0.6986 g

Answer 1

Zn(s) + 12(s) — Znly(s) Mass of dried Zinc lodide (Experimental Yield) = 0.6986 g weight = 0.6404 grams weight = 0.6544 grams molecular weight = 319.19 molecular weight = 253.81 molecular weight = 65.38 number of moles = weight/molecular weight = 0.6404/65.38 number of moles = 0.6544 / 253.81 = 0.0026 = 0.0098 theoretical yield = number of moles of limiting reactant X product molecular weight The reactant with less number of moles is known as limiting reactant. In this reaction le is limiting reactant theoretical yield = = 0.0026 X 319.19 = 0.83 grams