Question

Suppose that a catalyst lowers the activation barrier of a reaction from 121 kJ/mol to 59 kJ/mol . Part A By what factor would you expect the reaction rate to increase at 25 ∘C? (Assume that the frequency factors for the catalyzed and uncatalyzed reactions are identical.) Express your answer using two significant figures.

<Topic_6_kinetics Exercise 14.81 31 of 32 > A Review | Constants Periodic Table Suppose that a catalyst lowers the activation barrier of a reaction from 121 kJ/mol to 59 kJ/mol. Part A By what factor would you expect the reaction rate to increase at 25°C? (Assume that the frequency factors for the catalyzed and uncatalyzed reactions are identical.) Express your answer using two significant figures. V AED A o 2 ? Submit Request Answer Provide Feedback Next >

Answer 1

Solis Avrbenius Equation : K= Aexp (-Ealri) where K is flate Constant, A is pone - exponential factory Ea is activation, energy, R is molar gas constant and tie temperature in K. Since t is constant : = exp (- Ea(2) – Eaill) Jet ) ant inckz) = - Cfa 2) - Eall / RT) Eau) = 5 121 kJ/mol = 121000 Ilmo! Eacz) = 59. KT/mol = 59000 I) moj R = 8. 314 Ilmoik beic 12) = -(59000 - 121000)/(813148298.15) InC 52) = 25.0119 K2 = exp (25.0119) = 7028x10° thus rate constant & increase by a factor of 7.28 xlolo Since reaction sale is propostional tok, the rate also increases by a factor of tizexiono - U -