Question

The maximum amount of calcium sulfide that will dissolve in a 0.105 M calcium acetate solution is ___ M.

- The Ksp given for calcium sulfide is

8 × 10-6

Answer 1

The balanced equilibrium expression it given below. Let 't be the solubility of cas, then change in [Ca 2+] is tx, change in [5] is ta. We can insent these values in ICE table.

Cas(s) - Carta + 5lag) initial pure solid 0.10sm o change - + + final pure solid 0.105th + The Ksp expression is as follows: Ksp = [624] [52] = (0.105+2) (a) = 8x106 0.1058 + x² = 8x106 = 23+0.1054 -(8 x 10 b) = 0 = 2 = 0.000076135270672 M Amount of cas that will dissolve = a x molar mars (72.143 g/ml) = 0.005493 g/L Answer: a = 7.613x105m ㅠ ㅠ ㅠ