Question

Problems 1. According to the Ideal Gas Law, which of the following is/are correct for a gas cylinder of fixed volume filled with one mole of oxygen gas? Please explain each one. a. When the temperature of the cylinder changes from 15 °C to 30 °C, the pressure inside the cylinder doubles. b. When a second mole of oxygen is added to the cylinder, the ratio T/P remains constant. C. An identical cylinder filled with the same pressure of hydrogen contains more molecules because hydrogen molecules are smaller than oxygen molecules. d. When a second mole of oxygen is added to the cylinder, the ratio T/P decreases by 50%. (2) Suppose we have a sample of ammonia gas with a volume of 3.5 L at a pressure of 1.67 atm. The gas is compressed to a volume of 1.35 L at a constant temperature. Calculate the final pressure. Tatta 3. A sample of gas at 15 °C and 1.0 atm has a volume of 2.58 L. What volume will this gas occupy at 38 °C and 1.0 atm? V 7 4. A flashbulb of volume 2.6 cm contains Oz gas at a pressure of 2.3 atm and a temperature of 26 °C. How many moles of Oz does the flashbulb contain? Vi Ti (5. A quantity of gas occupies a volume of 16,5 L at 78 °C and 4.56 atm. What is the volume at STP? هم آه او 6. If 15.0 g of hydrogen sulfide gas occupies 10.0 L at STP, what is the molecular weight? V2 7. A chemist has synthesized a greenish-yellow gaseous compound of chlorine and oxygen and finds that its density if 7.71 X10 g/mL at 36 °C and 2.88 atm. Calculate the molar mass of the compound and determine its molecular formula. Y5 (8. The industrial synthesis of nitric acid involves nitrogen dioxide with water to form nitric acid and nitrogen monoxide. Write and balance the equation. How many moles of nitric acid can be prepared by using 450 L of NO2 at a pressure of 5.00 atm and 295 K? 9. Quicklime (Cao) is produced by the thermal decomposition of Caco. Calculate the volume of CO2, at STP. produced from the decomposition of 152 g of CaCO3. CaCO3(s) Cao (s) + CO2(g) 10. A 2.14 L sample of hydrogen chloride gas at 2.61 atm and 28 °C is completely dissolved in 668 mL of water to form hydrochloric acid solution. Calculate the molarity of the acid solution. Assume no volume change. (Calculate moles then divide by 668 mL-note units) 11, Calculate the volume of oxygen at 80 °C and 823 mm Hg required for the complete combustion of 7.64 L of acetylene (C2H2) at STP. Write and balance the equation first. 12. Forty miles above the earth's surface the temperature is -23 °C, and the pressure is only 0.20 mm Hg. What is the density of air (molar mass = 29.0 g/mol) at this altitude? 22.4L lomo con 1 152 g Calos mul Carlos I nel co2 1 9 Inel Calog

Answer 1

1 Griven : volume of cylinder is constant. mole of oxygen = 1 mol as T = 150 = 288k T2= 300 - 303k as volume and mol is constant. so pa T So, if temperature is doubled then only pressure becomes twice, Toice ! but here To is not twice of Ti. this statement is not correct. initial mole = 1 mole final mole = 2 mole aut constant volume pant P = constant T _ . constant then ratio of I becomes half So, when we double mole in order be that constant as 7 becomes - 7 becomes ŹĆ x100'l. = 50% so s. de creare = and statement this also explains statement id. is correct 6 is not correct. C Scanned with CamScanner

c) If identical cylinder contain H₂ at same mole be same of same & pressure volume of O, and then same temperature their number of الها as PV = nRT constant so, n will be same as '02. Initial volume of NH₃ (V.) = 3.51 Initial pressure of NH₃ (P.) = 1.67 atm final volume (12) - 1.351. let final forlessure be le i at constant Temperature and mole. PV = constant - PV = P2 V2 :) P PV V 3.5 LX 1.67 atm 1.35L = 4.33 atm. 3) T = 15°c = 288k P = 1 atm V = 2:58 L T2 = 38°C = 311k P2 = 1 atm bet volume be V2 ICScanned with Camscanner

gas at constant amount of PV = constant PV = B - 2 1 atmx 2.58L 288k I atm x - 311k .: 311 82.58 V2 = 288 = 2.786 L 4) Pressure of O2 = 2.3 atm Volume = 216 cm3 = 216 x103 l { I em?. mis 10-3L9 PVE ORT mole of O2= PV RT - 2.3 atm x 2.68103 0.082 Latm mol kody 299 K - 0.244X10-3 mol = 2.44810-4 mol CS anned with CamScanner