Question

If. How many calories are required to change the temperature of 1003 g of gold from 23.5 °C to 85.0°C? The specific heat of ethanol is 0.1256 J/g"C. A. 1350 cal B. 3300 cal C. 6750 cal D. 1850 cal E. 7750 cal 19. Which is NOT a physical property of matters? A. Boiling Point B. Combustibility C. Specific Heat Capacity D. Solubility E. Density Ih. What is the charge on Pd atom in Pd(NO2)2? A. Pd+ B. Pd+ C. Pd" D. Pd5+ E. Pd+ 11. Which compound will NOT be water soluble? A. Hydrochloric Acid B. Lithium Arsenate C. Iron(III) Sulfide D. Sodium Chloride E. Mercury(II) Nitrate 1j. Which of the following can be classified as an ionic compound? A. Argon B. Calcium Carbide C. Water D. Sulfur Hexafluoride E. Oxygen gas

Answer 1

(1) According to me, there should be collection otherwise this question can't be solved. specific heat of gold should be 0.1256 I/ge. Ans: where; formula Used: Q = calories required Q = mc (Tf - Ti) | ma mass of gold = 1003 gram ca specific heat of gold - 0.1256 J\J*c The final Temperative = 85.0°C Ti = Initial Temperatue = 83.5°C So, Q = me (If-To) 1003 gram X 0.1256] x [85.0°C -83.5°c) Joule = 7747.5732 = 11850 calories (1 Joule = 0o 238 Cal] oht":D is consect-

(2) (A) Boiling point is physical property. Because there is no change in molecular structure of theo (B) combustibility is chemical property because wher an substance undergoes combustion reaction with Oxygen, it leads to new substance e molecular structure change). (1) specific Heat capacity is physical property Because it is the heat energy required to raise tempuature of substance feu unit mass, Noty change moleculas stucture. (directly involve in) 0 solubility is physical pusperity because it dissolu the substance into solvent, not change the molecular stemture of substance while cdissolving. (E) Density is physical properity because it is the ratio of mass and volume. There is no change in molecular structure. (option - 6) Ane

(3) charge on Pd atom in Pd (NO2) :- I charge on No So; Pd, (NO2). Pd -2=0 1 Pd X1 + 2X(-1)=0 [This equation is Pd=+27 iol, Pdt2. Johth: A equal to 2040 Because there is no charge on its outer de | sphere, ie, [Pd (No,), 7° Ang
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