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How many grams (to the nearest 0.01 g) of NH4Cl (Mm = 53.49 g/mol) must be...

How many grams (to the nearest 0.01 g) of NH4Cl (Mm = 53.49 g/mol) must be added to 750. mL of 1.188-M solution of NH3 in order to prepare a pH = 9.90 buffer?

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Answer #1

PH Solution :- pH = 9.90 pH + POH = 14 . pos = 14- pH = 14-9.90 pon = 4.107 Kb for NHZ E 1.8x175 pkb = -log ko = 4.75 for NH3mass of Nhyll 53.49 x 1.188% 750x103 = 0.2239 X 1.188x te5 mass of NH4Cl = 0.2239 x 53.49 * 1.188 x 750 X10° = 106 70.9822x10

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