Question

-/1 points | WERTZCAMS3 1.P.026.0/10 Submissions Used How many moles of CF, can be produced when 8.89 mol C reacts with 3.62 mol F2? mol How many moles of each reactant are left over? (Note that at least one of the reactants must disappear.) C remaining F2 remaining mol mol Additional Materials Chapter 1 - The Early Experiments

Answer 1

C   +2 F2 ----------------> CF4

1 mole of C react with 2 moles of F2

8.89 moles of C react with = 2*8.89/1   = 17.78 moles of F2 is required

F2 is limiting reactant

2 moles of F2 react with excess of C to gives 1 moles of CF4

3.62 moles of F2 react with excess of C to gives = 1*3.62/2   = 1.81moles of CF4

2 moles of F2 react with 1 moles of C

3.62 moles of F2 react with = 1*3.62/2 = 1.81moles of C

the no of moles of excess reactant remains after complete the reaction = 8.89-1.81 = 7.08moles

C remaining =7.08moles

F2 remaining = 0 moles