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Question 39 of 68 What mass of KOH would need to be dissolved in 500.0 mL of water to produce a solution with a pH of 12.40?
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Ans: H = 12.40 pH = -log [H +] = 12.40 » [+] = 10 -12.40 = 3.98 x 10-13 WoW Guy Lon] = 1x 10-14 & Tony = 1x 10-14 3.98 x 10-nkoH = 0.5 X 0.025 moles = 0.0125 moles. Now, Number of moles (MX) = given weight in grams Molar mass Molar mass of KOH = 56.

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