![QUESTION 26 The electronic structure of the aluminum atom is [Ne]3s23p. The electronic structure of the aluminum ion is al [N](http://img.homeworklib.com/questions/1522ce80-d4d3-11eb-b9b7-eb8e1b6dc1f2.png?x-oss-process=image/resize,w_560)
Homework Answers
Ans:- Aluminium ion generally exist in +3 oxidation state
So electronic configuration of Al ion will be (Ne)
So answer is D.
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QUESTION 26 The electronic structure of the aluminum atom is [Ne]3s23p. The electronic structure of the...
43) The electron configuration of the sulfide ion (S2-) is A) [Ne]352 B) [Ne]3s23pl C) [Ne]3s23p4...
43) The electron configuration of the sulfide ion (S2-) is A) [Ne]352 B) [Ne]3s23pl C) [Ne]3s23p4 D) [Ne]3p2 E) [Ne]3s23p6
atomic structure question a) draw the energy-level diagram and write the electronic configuration for zirconium (eleme...
atomic structure question a) draw the energy-level diagram and write the electronic configuration for zirconium (element 40). b) use the diagram to explain why the Zr4+ ion exists. c) compare the stability of the Zr atom and the Zr ion. account for any differences in their stability.
2. (20 points) Answer the following questions based on the given ground state electron configurations Ne]3S23p,...
2. (20 points) Answer the following questions based on the given ground state electron configurations Ne]3S23p, [Ne]3S2?3p*, [Ne]3S?3p* a) Identify the above elements b) Arrange the element in order of decreasing atomic radius. Explain your reasoning in complete sentences c) Arrange the elements in order of increasing first ionization energy. Explain your reasoning in complete sentences. (Hint: be careful with the exceptions) d) In one of the element, there is a huge jump between the third ionization energy and the...
Question 22 5 pts The electronic configuration for boron is 1s2 2s22p1, and the electronic configuration...
Question 22 5 pts The electronic configuration for boron is 1s2 2s22p1, and the electronic configuration for aluminum is 152 252 2p6 352 3p1. It requires 8.298 eV to remove the outermost electron (2p1) from boron. What can you say about the energy required to remove the outermost electron from aluminum (3p 1)? Since each is the outermost electron around the atom, the energy required will be equal to 8.298 eV. Since each electron is in a p orbital, the...
Question 22 5 pts The electronic configuration for boron is 1s22s22p1, and the electronic configuration for...
Question 22 5 pts The electronic configuration for boron is 1s22s22p1, and the electronic configuration for aluminum is 1s2 2s22p6 352 3p1. It requires 8.298 eV to remove the outermost electron (21) from boron. What can you say about the energy required to remove the outermost electron from aluminum (3p1)? Since each is the outermost electron around the atom, the energy required will be equal to 8.298 ev. Since each electron is in ap orbital, the energy required will be...
1. The electron configuration of a Ti atom is A) [Ne]3s23d2 B) [Ne) 3s4d2 C) [Ar)4s23d...
1. The electron configuration of a Ti atom is A) [Ne]3s23d2 B) [Ne) 3s4d2 C) [Ar)4s23d E) IAr13d 2. The electron configuration of an Fe ion is 3?The total number of electrons in the 3d orbitals of a copper atom is A) 6 B) 7 C)8 D) 9 E) 10 4. How would you expect the molecule 1,10-phenanthroline (shown below) to function as a ligand? ?-? ?-? C--H A) B) C) It would be expected to be a monodentate ligand....
0.747 m/s Question 22 5 The electronic configuration for boron is 1s22s22p1, and the electronic configuration...
0.747 m/s Question 22 5 The electronic configuration for boron is 1s22s22p1, and the electronic configuration for aluminum is 1s22s22p6 352 3p1. It requires 8.298 eV to remove the outermost electron (2p1) from boron. What can you say about the energy required to remove the outermost electron from aluminum (3p1)? Since each is the outermost electron around the atom, the energy required will be equal to 8.298 eV. Since each electron is in a p orbital, the energy required will...
Question 22 5 pts The electronic configuration for boron is 152 2s22p1, and the electronic configuration...
Question 22 5 pts The electronic configuration for boron is 152 2s22p1, and the electronic configuration for aluminum is 1s2 252 2p6 352 3p1. It requires 8.298 eV to remove the outermost electron (2p1) from boron. What can you say about the energy required to remove the outermost electron from aluminum (3p1)? Since each is the outermost electron around the atom, the energy required will be equal to 8.298 eV. Since each electron is in a p orbital, the energy...
1. a) Write the electronic configuration for the atom of Co b) Draw the box diagram...
1. a) Write the electronic configuration for the atom of Co b) Draw the box diagram for the valence electrons of Co c) From the complete set of the 4 n° quantum ns to one of the highest energy electrons for the d) Write the electronic configuration for the ion Co +3
Please explain each step. O ELECTRONIC STRUCTURE Identifying the electron added or removed to form an...
Please explain each step.
O ELECTRONIC STRUCTURE Identifying the electron added or removed to form an ion For each atom in the table below, write down the subshell from which an electron would have to be removed to make a electron would have to be added to make a -1 anion. cation, and the subshell to which al The first row has been completed for you. atom subshell from which electron removed to form el cation subshell to which electron...
43) The electron configuration of the sulfide ion (S2-) is A) [Ne]352 B) [Ne]3s23pl C) [Ne]3s23p4 D) [Ne]3p2 E) [Ne]3s23p6
2. (20 points) Answer the following questions based on the given ground state electron configurations Ne]3S23p, [Ne]3S2?3p*, [Ne]3S?3p* a) Identify the above elements b) Arrange the element in order of decreasing atomic radius. Explain your reasoning in complete sentences c) Arrange the elements in order of increasing first ionization energy. Explain your reasoning in complete sentences. (Hint: be careful with the exceptions) d) In one of the element, there is a huge jump between the third ionization energy and the...
Question 22 5 pts The electronic configuration for boron is 1s2 2s22p1, and the electronic configuration for aluminum is 152 252 2p6 352 3p1. It requires 8.298 eV to remove the outermost electron (2p1) from boron. What can you say about the energy required to remove the outermost electron from aluminum (3p 1)? Since each is the outermost electron around the atom, the energy required will be equal to 8.298 eV. Since each electron is in a p orbital, the...
Question 22 5 pts The electronic configuration for boron is 1s22s22p1, and the electronic configuration for aluminum is 1s2 2s22p6 352 3p1. It requires 8.298 eV to remove the outermost electron (21) from boron. What can you say about the energy required to remove the outermost electron from aluminum (3p1)? Since each is the outermost electron around the atom, the energy required will be equal to 8.298 ev. Since each electron is in ap orbital, the energy required will be...
1. The electron configuration of a Ti atom is A) [Ne]3s23d2 B) [Ne) 3s4d2 C) [Ar)4s23d E) IAr13d 2. The electron configuration of an Fe ion is 3?The total number of electrons in the 3d orbitals of a copper atom is A) 6 B) 7 C)8 D) 9 E) 10 4. How would you expect the molecule 1,10-phenanthroline (shown below) to function as a ligand? ?-? ?-? C--H A) B) C) It would be expected to be a monodentate ligand....
0.747 m/s Question 22 5 The electronic configuration for boron is 1s22s22p1, and the electronic configuration for aluminum is 1s22s22p6 352 3p1. It requires 8.298 eV to remove the outermost electron (2p1) from boron. What can you say about the energy required to remove the outermost electron from aluminum (3p1)? Since each is the outermost electron around the atom, the energy required will be equal to 8.298 eV. Since each electron is in a p orbital, the energy required will...
Question 22 5 pts The electronic configuration for boron is 152 2s22p1, and the electronic configuration for aluminum is 1s2 252 2p6 352 3p1. It requires 8.298 eV to remove the outermost electron (2p1) from boron. What can you say about the energy required to remove the outermost electron from aluminum (3p1)? Since each is the outermost electron around the atom, the energy required will be equal to 8.298 eV. Since each electron is in a p orbital, the energy...
Please explain each step.
O ELECTRONIC STRUCTURE Identifying the electron added or removed to form an ion For each atom in the table below, write down the subshell from which an electron would have to be removed to make a electron would have to be added to make a -1 anion. cation, and the subshell to which al The first row has been completed for you. atom subshell from which electron removed to form el cation subshell to which electron...
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