Question

What is the solubility of PbF₂ in a solution that contains 0.0550 M F⁻ ions? (Ksp of PbF₂ is 3.60 × 10⁻⁸)

Answer 1

kep of Pb Fe (given ) = 3.60 x 108 for dissouration of Pbfz, Pbfg (s) - Portalt at laa) 0 0.055 tu (tar) n (0.055+2n) Huw Kap is given by, kop = [ Pb 2+ ][ F 7 = 3.68108 (2) (0 1055+ auf = 3,6x108 0.055 Value of ksp is very small, soo (0.055 +24) a 10.055) 2 = 3.6810 8 260.003025) = 3168108 x = 3.6x108 31025 x 103 u= 1019 8105 - 1.28105 Thus, molar solubility of Boty = 1.28105