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Consider the reaction Afaq) + B(ag) A3 C(aq) + (aq), which has an equilibrium constant, K, equal to 3.4. 1. If one begins a r
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Again , 0:600 moles of B is added. Wow. 0.5ls Al = 0.385-2 te = 0.115 + x 81-0.01+0.5 - [0] = 0.115 ta Hence e 2, (0.116 +2

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