Starting from the appropriate free energies of formation (provided below) calculate the values of ∆G° (in kJ) and E°cell (in V) at 298 K for the following reaction, 2 Na(s) + 2 H2O(l) <-----> 2 Na+(aq) + 2 OH-(aq) + H2(g) DfG°(Na(s)) = 0.00 kJ mol-1 DfG°(H2O(l)) = -237.13 kJ mol-1 DfG°(Na+(aq)) = -261.91 kJ mol-1 DfG°(OH-(aq)) = -157.24 kJ mol-1 DfG°(H2(g)) = 0.00 kJ mol-1

Starting from the appropriate free energies of formation (provided below) calculate the values of ∆G° (in...
Starting from the appropriate free energies of formation (provided below) calculate the values of ∆G° (in kJ) and E°cell (in V) at 298 K for the following reaction, 2 Cu+(aq) -----> Cu2+(aq) + Cu(s) DGf°(Cu+(aq)) = 49.98 kJ mol-1 DfG°(Cu2+(aq)) = 65.49 kJ mol-1 DfG°(Cu(s)) = 0.00 kJ mol-1
Starting with the standard free energies of formation from the
following table, calculate the values of ΔG° and E°cell of the
following reactions.
Substance
ΔΔG°f
(kJ/mol)
FeO(s)
-255.2
H2(g)
0
Fe(s)
0
H2O(l)
-237.2
Pb(s)
0
O2(g)
0
H2SO4(aq)
-744.5
PbSO4(s)
-813.0
1) FeO(s) +H2(g) ----Fe(s) +H2O(l)
change in G=18kj
E Cell= v
2) 2Pb(s)+O2(g)+2H2SO4(aq)--------2PbSO4(s)+2H2O(l)
change in G=-611.4
E°cell
= V
Consider the following values of standard enthalpies and free energies of formation at 298 K: Chemical Species C2H2(g) C2H6(g) AH (kJ mol-') +228 -84 AGI° (kJ moll) +211 -32 Determine whether the reaction: C2H2(g) + 2 H2(g) → C2H6(g) is: • spontaneous and exothermic • spontaneous but endothermic • non-spontaneous and exothermic • non-spontaneous but endothermic Show your working
Part A Based on the standard free energies of formation, which of the following reactions represent a feasible way to synthesize the product? Drag the appropriate items to their respective bins. View Available Hint(s) Help Reset 2CO(g)+02(8)+2CO2 (g) AG=-788.0 kJ/mol N2 (g)+O2(g)-2NO (g) AG= 173.2 kJ/mol 2Na(s)+02(8) -Na, O, (s) AGi=-451.0 kJ/mol 2C(s)+ H2(g)-C2H2 (8) 209.2 kJ/mol AGi Not a feasible synthesis Feasible synthesis
The standard Gibbs energies of formation for Cu2+ (aq) and Fe3+ (aq) are 65.49 kJ mol-1 and -4.7 kJ mol-1 respectively. What is the standard potential (Volts) at 298 K for the cell: 3Cu2+(aq) + 2Fe(s) + 2Fe3+ (aq) + 3Cu(s)
Consider the following chemical reaction and free energies of formation in the table: 4 NH3(g) + 7 O2(g) → 4 NO2(g) + 6 H2O(l) Calculate ∆G°rxn (kJ) for the reaction. Only enter a numerical value. Products or reactants ∆G°f, kJ/mol NH3(g) -17 O2(g) 0 NO2(g) +52 H2O(l) -237
(6 pts.) Using Hess’s Law and the values for Standard Enthalpies of Formation from the table provided, calculate the enthalpy of reaction ΔH°rxn (in kJ) for each of the following reactions: Standard Enthalpies of Formation substance ΔHf° in kJ/mol Mg(s) 0 MgO(s) -601.6 HCl(aq) -167.2 MgCl2(aq) -801.2 H2(g) 0 H2O(l) -285.8 Reaction #1: Mg (s) + 2HCl (aq) è MgCl2 (aq) + H2 (g) Reaction #2: MgO (s) + 2HCl (aq) è MgCl2 (aq) + H2O (l) 2. (4 pts.)...
Based
on the standard free energies of formation, which of the following
reactions represent a feasible way to synthesize the product? Drag
the appropriate items to their respective bins.
Reset Help 2Na(s) + O2(g) +Na2O2(s) AGE = -451.0 kJ/mol 2CO(g) + O2(g)+2C02(g) AGE = -788.0 kJ/mol N2(g) + O2(g) +2NO(g) AGE = 173.2 kJ/mol 2C(s) + H2(g) +C2H2(g) AGE = 209.2 kJ/mol Feasible synthesis Not a feasible synthesis
Use the standard free energies of formation (ΔGf°) of each substance to determine the value of equilibrium constant K at 25 °C for the following reaction. Click here for a copy of the Test 3 cover sheet. CO2(g) + 2 H2(g) ⇌ CH3OH(l) ΔGf° kJ/mol −394.4 0 −166.4 0 0.91 8.83 × 1039 1.13 × 10−40
1. Based on the standard free energies of formation, which of the following reactions represent a feasible way to synthesize the product? N2(g)+H2(g)?N2H4(g); ?G?f=159.3 kJ/mol 2Na(s)+O2(g)?Na2O2(s); ?G?f=?447.7 kJ/mol C(s)+2S(s)?CS2(g); ?G?f=67.1 kJ/mol Ca(s)+12O2(g)?CaO(s); ?G?f=?604.0 kJ/mol Feasible synthesis Not a feasible synthesis