Question

A 0.218 mol sample of Ar gas is contained in a 7.00 L flask at room...

A 0.218 mol sample of Ar gas is contained in a 7.00 L flask at room temperature and pressure. What is the density of the gas, in grams/liter, under these conditions?

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Answer #1


Molar mass of Ar = 39.95 g/mol

use:
mass of Ar,
m = number of mol * molar mass
= 0.218 mol * 39.95 g/mol
= 8.709 g

Now use:
Density = mass / volume
= 8.709 g / 7.00 L
= 1.24 g/L

Answer: 1.24 g/L

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