Question

Assign an EIZ designation to each of the molecules below. NH₂ H₃C ci IO B O A = Z, B = 2 A =E, BEZ A = Z, B = E A = E, B = E

Answer 1

Answer:. A= Z, B= E

Detailed discussion has been provided in the pictures attached.
Pon E/Z isomerism, > If higher priomly group is present on same side of double bond then it is z ( Zusammen isomer). of If higher priority group is present on opposite side of double bond then it is E (Entgagen isomer) Now, for assigning priority the CIP (Cahn- Ingold- freelog) reile is followed which says: of The atoms linked direilly wilk the double bond carbon alómare first considered. Higher the atomic number of an atom, higher will be its priority. " If 2 atoms directly linked to the double bond carbon atom becomes same, then next set of alom is considered and this process continues enlil a point of difference is reached.

Wilk böse afore-mentioned Set of rules now let's approach the given molecules in question? The 2 carbons of double bond are first labelled as C1 and C2. This labelling is done arbitarily just in onder to denote 2 different carbon atom. @ Noro fon C1, it is direcilly atlached lo A-atom one side and c on the other. i atomie no. of a (14) ) atomie no. of e(6). Hence, priority of ct > priority of C. The higher priority group is labelled as & lower priority group is labelled as Ⓡ . 3 Similarly for C2, it is directly allâched to F-atom on one side and c ar on the other. salonie no.9 F (9) atomic no. of c (6)

Hene, priority, on a priority fe (labelled os © Thus, we see for both Cs and C2, the 2 higher priority groups are the same side. of the double bond ( bolt located on the down side as can be seen on the structure drawn). ... The given molecules is Z-isomes ® mo cla . ® Molecule B : *-- Like the previous molecule, the 2 double bond carbon atoms are first labelled as c1 and 22. You C1, thot it is directly attached to carbon alóms on either side. Hence, now according to second point of CIP rule the next set of atoms are so considered. The upper carbon atom is further allāched to 22 and 1H.

The lower carbon atom is linked lö 24 and 10. Now, as the atomic no. of C (6) atomic no. of 4 (1). u. The upper carbon atom linked to 26. & 14 has greatis pmianty Chân lower carbon atom linked to 16 & 2 H." 3 C2 is directly altached to H and Cl on either Alomic no. of al (17) Alomie no. of 4(1). Thus, priority of a pricinity of H (labelled as ③). (labelled as A) ION side. & Thus, we see the 2 higher priority groups are on the opposite side of double bond ( upperside fon el, downward side fom c2) The given molecule B is E isomer ! Answer: A = Z, B E