Question

Determine the amount of heat involved in a chemical change using. Hess's Law Question 2C(s) + 0,(g) + 2 CO(g) AH = -222 kJ 2 H, (g) + O2(g) + 2H2O(g) AH = -484 kJ H,0(1) H2O(g) AH = +44 kJ Use the thermochemical data above to calculate the change in enthalpy for the reaction below. H,0(1) + C(s) + CO(g) +H, () . Your answer should have three significant figures. Provide your answer below: Activity Details You have viewed this topic asticited 2020.6.12 PM

Answer 1

Answer

Enthalpy of the resultant reaction is +175kJ

Explanation

ROLL DOM5 Page No. Date 1 1 Answer Enthalpy of Given Resulting Reaction ý +175 kJ Explanation 2 - We are being Enthalpy change of a asked to find the Reaction given. by wling Helses lene. We knone that Hessel' lo states that without Regardin of the Multiple stages on steps da Realking, The Total Enthalpy charge for the Reaction is Sun charges We have a Target Equaloon H₂O (L) + ((o) Cocg + 1489 and the reactions and its chappe ly Enthalpice are given as follows

owy el Joulu Given Reactions and data 2 CCs) + O2(g) → z corgi SH=-222kg 2H₂ C92+ O₂(g) → 2H20 (9) JH = -48465 bou H₂O (g) = Alt 2+44 kg - let the Reations be 2 (Cs) + O2(g) → 2CO (9) 2 2 H₂(g) + Q (9) - 240 (g) - H₂O(l) → hocg) - © be a, b, c Equation So that we can have operations to get resulting Reaction so

I we - have a resultin Ho (1) + co Recution a colga+ 4 (g) Equation @ and first we looking for Target Equation We have C(6) at Resulting Reaution, We can devide left side of for that. quaction @ 72 @ = 2 (cs) + QCq) 2 cocg) at 2-222 % cot 10 cocg) CH= -222 AH-222 2-11] KT let the equation of Then Reverling equation and devidary by 2 D => 2497 0249) ~2400g) H248415

Reverling b 2 H₂O(g) + 2H₂(g) + O2(g) 04 2484 kg Reversal of a 2 Hoc) C let & be wand we have H₂ (g) + 22 (9) @ AH = 484_24215 @ 404) in the left part ma so ② may held as it is म., o पाणी 24 44 kg By adding equations @ @ o and ② Is Eenahing @ +@+©

- <(s) + % 0,49) H₂OCG Hod logo H₂ + y ₂ cq hocg d shillik e She 29214 C 64444 - aterc. - C(s) + kg (g) + H2O(g) + H₂O) Colg) + H₂ (9) + + 2 g) +40 so serulting Equation giver co + H₂O(4) - Colgt (9) - Sime dt etc is added et altscentius = GHd + Alet Olte 2 - 111 kg + 242 kg + 44 kg z+175 kJ Enthalpy of Repultury Reaching i +175 kJ