1) 2) 3) Please explain step by step so I can understand how answer was obtained...

Question

Question

1)

Given the following rate law, how does the rate of reaction change if the concentration of Z is tripled? Rate = k [X] [Y]2[z]

2)

At a certain temperature the equilibrium constant, Kc, equals 0.11 for the reaction: 2 ICI(g) = 12(g) + Cl2(g). What is the e

3)

CH4(g) + 2 H2S(g) = CS2(g) + 4 H2(g) A reaction mixture initially contains 0.74 M CH4 and 0.68 M H2S. If the equilibrium conc

Please explain step by step so I can understand how answer was obtained

science chemistry

Answer 1

Answer #1

1 answer is

② Rate law Rate = k [x] [V[z] according to sate law 31. a so 1st order reaction with respect z. we renow that Rate a [] :

Answer 2

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