Question

1. For the following reaction, K. is 9.7 at 305 °C. If initially the concentrations of all 3 gases were 0.089 M, what will be the concentrations of all three at equilibrium? BrCl3 (Ⓡ) + Cl2(e) S BrCls (8) Br Claipt C'zig to Brols (g) (0.089 + x) 9.7 10.089M 0.089M 0.0891 10.089 - x)² C - X - X X € 0.089M-X 0.08911-X 0.089n + X K :9.7 = (0.089M +x) 10.089M - x)(0.089M - x)

Answer 1

0.08172 Billz (g) + Cl (g) Ž Brilslg) 0.089 0.089 0.089 -2 -3 ta t 0.089-2 0-089-8 Kc = 9.7 =10.089+x) (0.089-3) 9-1= 0.089 +2 7.921x10 3 + x²-0.178 x 7.921x10 3 + x²-0.178x = 9.175x10s + 0.1032 x² -0.2812 - 1.250x10 3 = 0 x = 0.285 or 4.38x10-3 M a direction is [Brez] = 0.089 -(-4.38x103) = 0.0934M [ U₂] = 0.0934 M [Brds] = 0.0846M NaC2H302 / 4 (2 4302 & buffer is weat acid and its reversed than assumed. conjugate base