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You may want to reference (Pages 910 - 914) section 19.6 while completing this problem. Part B A voltaic cell employs the fol
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Mg(s) + Mg2+ + 2e- e°anode = -2.360 V Fe3+ + 3e- → Fe(s) Eºcathode = -0.040 V Eºcell = Eºcathode - E°anode =( -0.040 D-1 -2.3

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