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At 700 K, Kc = 1.56×10–2 for the reaction 2 HBr(g) ⇌ H2(g) + Br2(g). In...

At 700 K, Kc = 1.56×10–2 for the reaction 2 HBr(g) ⇌ H2(g) + Br2(g). In a given experiment, 0.050 mol of H2, and 0.050 mol Br2 are introduced into a 5.0-L flask. What is the equilibrium concentration of HBr?

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Answer #1

QHBr - H2 + Bra (9) (9) ke = 1.56x102 0.050 mol oos o mol. Initially o at equil ax (0.050-x) (0.050-x) equation for equilibri

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