Be sure to answer all parts. How much heat has to be added to 251 g...

Question

Question

science chemistry

Answer 1

Answer #1

ANSWER- Q = 2.53008 × 104 J

Solution-

We use equation, Q= mcdT

Where, Q= Heat Transferred

m= mass, c= specific heat , dT = change in temperature

Given data, m= 251 grams

c= 0.448 J/g oC

dT= Tfinal - Tinital = 250-25 = 225oC

Q= 251 × 0.448 × 225 J = 25300.8 J = 2.53008 × 104 J

Answer 2

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