Question

In a 0.640 M aqueous solution of a monoprotic acid, 3.89% of the acid is ionized. What is the value of its Ka?

Answer 1

Det equs cogzwedere a monoprolic acid HA HA +40 AO + Hot concentrabon of HR = 0.640 M y of ioniwalion. [AB, X100 = 3-89 - [A-] x100 0.640 = [A] = 3.89 x 6.640 = 0.025 100 0.025. bet LA-I equal to ao cond its value ip HA + H₂O AO & thot Inilialley 0.640 finally 0.640-8 K Degree of diwpocrabion (kal = [A]["460" THAI a

[160] zis comu lan! ays prevent in love ko : ak 1. « 0.640-U = 12 0.640-2 (0.025) ? 0.640-0.025 6.25 x 10-4 ak: eta 0.615 aka: 1 x 10-3 Disocialion conwland ka is 1x1013. cAnwevery