Question

1. Calculate the solubility (in grams per liter) of Fe(OH)₃ , which has a K_sp of 4.01 x 10^-15 at a given temperature. Report your answer to 3 significant digits, but do NOT include units.

2. What is the solubility of Ag₂CO₃ (in milligrams (mg) per liter) in an aqueous solution of 0.15 M Na₂CO₃? Report your answer to 2 decimal places, but do NOT include units!

Answer 1

Fe(OH)₂ (ap) & Fe 13 + 304 Se molar solubility of Ferrie kap- [Fe +3] [OH-] kep- sx 185) 3 hydroxide 3 Kyp 2754 s. when he said 1015 ut manos 4.01x10-15 4 1.498 10-16 V 27 an d real l. 1o 4 x 16 mol mass of Fe(OH) = 107g/mol massa mole & molar mash - wiele rane x '67 er forment = 1.104 x154 mol x 107g/mol =0.0118 872 AZ CO₂ (aq) Z 2 Ag+ (aq) + CO₂h-ag) Kep [Azt] ² [ coz an] But in 0.15m Nascos. (Na2CO₃ is comie hence fully dissociated as NALCO₃ → 2Na+ (aq) + 10 tags 2x0.15 0.15m

+0.1 û 0.15M Total cor in solution - Sto.10 as s << 0.15 kop: [ Ag+ ] ² [ Coz do 8x 1612 (23) ²x 0.15 8x10-12 45 x 0.15 gha 8x10-12 = 1.33x10-11 - 4x0.15 Sa 3. 65x106m 3.65x156 mol molar mass of Ag, Coz= 216 g/mol so 3,65x166 mol x 276 g/mol = 1.0079 x 10-3 solubility - 1.008 my = 1:02mg/e