Question

Pour 2.5 mL of the 1M glucose (C6H12O6) solution from the flask into the 100 mL volumetric flask.

Use the “dilution equation” to determine the volume in mL for the required 0.025M solution, given that the original solution is 1M and you used 2.5 mL

Fill the volumetric flask to the 100 mL mark with distilled water. Note: The flask already contains a volume of 2.5 mL.

1. Compute the volume of the diluted 0.025 M solution.  

2. What volume of solute did you use to prepare the 0.025 M glucose solution?  
3. What volume of solvent did you use to prepare the 0.025 M glucose solution?

4. What is the volume of the solution you prepared?

5. How many moles of glucose are present in the diluted solution?

Answer 1

Here, M, IM Vi=2.5ml Mazo (wata) V₂ = n me Muit = 0.025 Muis Unix = MV & Mel2 hen $ 0.025 (2.5 tu) = 1*2.5 +0 $ ns 215 - 2,5 X0.025 - 0.025 a n=97-5m2) then (1) volume of diluted solution = 2.5797.5 = 1100 mL) (2) solute = 12.5 my (3) Solvent = 137.5my (4) Solution - 100 ml ③ moles of Wlucoses in diluted s Mile = { 12-5800-3 -4 2.54193