Question

Water vapor accounts for part of the gas volume and S8 lle volum u sued must be corrected for the water vapor present. The vapor pressure of the water depends on temperature and the vapor pressure of water (PH,o) at different temperatures can be found in Table 1. If a Ph,o value at a particular temperature is not usted in the table, then it has to be found through the interpolation method from two known Pho values at two nearest temperatures assuming a linear relationship in the narrow range. (See the section titled “Linear Interpolation” near the front of this manual). Do not crudely estimate a Ph,o value in a rough fashion: use of accurate Pho values is very important in the calculations. This is particularly true for higher temperatures at which a small variation in temperature brings about a large change in PH,0. Dalton's Law of Partial Pressures tells us that the total pressure exerted by a gas mixture is the sum of the partial pressures. The gas sample in this experiment is a mixture of air and water vapor, Peas = Pair + PH₂O
Find P air and V air ..

Answer 1

T°C VGAS, Puzo, Vair, mL Pa torr Par = P -PH2O mL torr V PE-PH20)/PEX Vair, ml (result of previous column) 5.7625 66.8 7.95 205.119 7.95 x 540.371 / 745.490 179.452 7.59 x 566.038 / 745.490 5.7629 62.4 7.28 163.896 7.28 x 581.594 / 745.490 5.6795 60.7 7.12 156.560 7.12 x 588.93 / 745.490 5.6247 56.0 6.78 123.925 745.490-123.9 6.78 x 621.565 / 745.490 56.0 6.78 123.925 51.6 6.45 102.181 5.6530 51.6 6.45 102.181 6.45 x 643.309 / 745.490 5.5659 47.5 6.18 75.711 6.18 x 669.7789 / 745.490 5.5524 745.490-205.119 = 540.371 745.490-179.452 = 566.038 745.490- 163.896 = 581.594 745.490-156.560 = 588.93 745.490-123.925 = 621.565 745.490-102.181 = 643.309 745.490-75.711 = 669.7789 745.490-64.853 = 680.6369 745.490-47.100 = 698.3899 745.490-31.844 = 713.6459 745.490-22.389 = 723.1009 745.490-17.542 = 727.9479 745.490-11.992 = 733.4979 43.3 5.92 64.853 5.92 x 680.6369 / 745.490 5.4050 36.8 5.65 47.100 5.65 x 698.3899/ 745.490 5.2926 30.6 5.45 31.844 5.45 x 713.6459 / 745.490 5.2172 24.4 5.29 22.389 5.29 x 723.1009 / 745.490 5.1311 19.5 5.18 17.542 5.18 x 727.9479 / 745.490 5.058 14.1 14.1 5.05 5.05 11.992 11.992 5.05 x 733.4979 / 745.490 4.9688

Y-Values y= 0.015x + 4.760 R = 0.985 volume of air Y-Values - Linear (Y-Values) -300 100 -200 -1000 temperature in degree celsius

y= 0.015x + 4.760 R= 0.985 volume of gas in ml niiniiniiniin + 10 50 60 70 80 20 30 40 temperature in degree celsius

y = 0.015x + 4.760

put y = 0 to find x intercept

0 = 0.015x + 4.760

X = -4.760/0.015 = -317.340C

So value of absolute zero according to best fit line is -317.340C

Actual value absolute zero is -273.150C