You are working in a lab and need to make a buffer with a pH = 5.50. You have 5.00 M NaOH and 5.00 M HCl available. You observe that malonic acid (HO2CCH2CO2H or H2A) has pK1 = 2.847 and pK2 = 5.696. Given the mass of malonic acid needed from the last problem, how many mL of NaOH solution is needed to give a pH of 5.50 in the buffer solution? Assume that you will make 500. mL of the buffer with a total buffer concentration of 0.100 M. Mass of malonic acid = 5.2 grams


You are working in a lab and need to make a buffer with a pH = 5.50. You have 5.00 M NaOH and 5.00 M HCl available. You observe that malonic acid (HO2CCH2CO2H or H2A) has pK1 = 2.847 and pK2 = 5.696. You only have pure malonic acid available in the lab. If you want to make 500 mL of a buffer with a total concentration of 0.100 M buffer components, what mass of malonic acid do you need...
Consider a 0.0100 M solution of malonic acid (H2A) with pKa1 = 2.847 and pKa2 = 5.696 a. Calculate the pH of the solution. b. Calculate the fraction of malonic acid existing as A2-. Does the second dissociation step make a significant contribution to the H+ in solution?
3. You are asked to make a buffer solution with a pH of 3.40 by using 0.100 M HNO, and 0.100 M NaOH (aq). a. Explain why the addition of 0.100 M HNO2 to 0.100 M NaOH(aq) can result in the formation of a buffer solution. Include the net ionic equations for the reaction that occurs when you combine HNO2 (aq) and NaOH(aq). Determine the volume, in ml, of 0.100 NaOH(aq) the student should add to 100 mL of 0.100...
Calculate the grams of sodium acetate required to make 250.0 mL of a pH 5.50 buffer solution using 0.100 M acetic acid (Ka of 1.8x10-5).
To make 1.00 L of a 0.100 M H2PO4- / HPO42- buffer at pH 6.90 and you start with the NaH2PO4, A. Calculate the mass of NaH2PO4 needed to make the buffer. B. Should HCl or NaOH be added to make the final buffer? Calculate the number of moles of HCl or NaOH that needs to be added. Note: formula mass of NaH2PO4 is 120.
Calculate the pH of a buffer made from mixing 10.0 mL of 0.100 M NaC3H2O, and 10.0 mL of 0.100 M HC,H,O2 pH 4.76 Calculate the pH of the buffer when 5.00 mL of a 0.0100 M NaOH solution is added. pH Calculate the pH of the buffer when 5.00 mL of a 0.0100 M HCl solution is added.
5. You need to make 500.0 mL of a buffer with a pH of 2.20. You have the following substances to work with: 0.100 M NH3 Solid NaN3 Solid NaClO2 0.100 M HClO2 Solid NH4Cl Solid Na2SO3 0.100 M HN3 Solid NaHSO3 Ka for HClO2 = 1.1x10-2 Kb for NH3 = 1.8x10-5 Ka for HN3 = 1.9x10-5 Ka1 for H2SO3 = 1.7x10-2 Ka2 for H2SO3 = 6.4x10-8 (Assume that the addition of solid does not change the volume of the...
Prepare 250.00 mL of a 0.1 M carbonate buffer with a pH of 9.5. Use sodium bicarbonate NaHCO3 , 0.100 M HCl solution and 0.200 M NaOH solution. How do you make this buffer? Givens: Carbonic acid pKa1 = 6.35 | pKa2 = 10.33 Molar mass NaHCO3 = 84.01 g/mol
You are asked to prepare 500. mL 0.150 M acetate buffer at pH 5.00 using only pure acetic acid (MW = 60.05 g/mol, pKa = 4.76), 3.00 M NaOH, and water. How many grams of acetic acid will be needed to prepare the 500. mL buffer? Note that the given concentration of acetat refers to the concentration of all acetate species in solution. mass: What volume of 3.00 M NaOH, must be added to the acetic acid to achieve a...
You work in a research lab with a chemist who asks you to make 500.0 mL of a formic acid/sodium formate buffer solution with pH = 4.10. Formic acid is HCOOH(aq); sodium formate is NaHCOO(s) and is soluble in water. The total concentration of formic acid + formate ion in the buffer is to be 0.120 M. Ka(HCOOH) = 1.77 × 10–4 (pKa = 3.75). In the storeroom, there are the following reagents: (i) solid sodium formate, (ii) a 3.00...