Question

Suppose 1.09 g of zinc chloride is dissolved in 300. mL of a 66.0 m M aqueous solution of potassium carbonate. Calculate the final molarity of chloride anion in the solution. You can assume the volume of the solution doesn't change when the zinc chloride is dissolved in it. Be sure your answer has the correct number of significant digits. (M)

Please only answer if you are 100% sure you know how to do it, two questions iv paid extra for have been wrong :( thank you!

Answer 1

ZnCl2 + K₂ 103 Zn 103 +2KC1 lioggi alle 1.098 IN nch2 = 0.008 mol 136.2869(my - polo 300 m2 of a 66 mh ag. sasa CO₂ = 300 x 10-3 lit x 66X10-3 M MISSONID tra 01 02 mol s. 0.008 mol ZnCG will react to for 2x0:008 ml kel ? PwC TOUCH 0.016 mol KcJ 21 PU?cq Osmo se er - bout n otanty of ct = 1 Bre o. Oi6 mol bunda 0.3ut 01053 MB ON yeur 1 2 ? in vir hoy en sirry at 7] 2 890 uka ow - en W