Question

Pb^2+ +2e- __> Pb e=-0.13V

Ag+ +1e-__> Ag e=+0.80V

Pb(s)| Pb²⁺ (1M) || Ag⁺ (1M) | Ag(s)

Determine which of the following statements about the cell shown are True or False.

The silver half-cell is the cathode.
True False  The mass of the silver electrode is decreasing.
True False  Anions move to the silver half-cell.
True False  Electrons are spontaneously produced in the lead half-cell.
True False  The cell, as represented by the line notation, is a voltaic cell.
True False  The standard cell potential, ξ^o, equals 0.67 V.
True False  As the reaction proceeds, the concentration of the silver ions increases.
True False  The silver electrode is the anode.

Answer 1

the silver half-cell is the cathode = true (because silver is getting reduced and reduction occurs at cathode)

the mass of silver electrode is decreasing = false ( the mass silver electrode increases due to deposition)

anions move to the silver half-cell = false(anions moves towards anode)

electrons are spontaneously produced in the lead half-cell = true ( lead acts as anode and oxidation occurs there)

the cell, as represented by the line notation, is a voltaic cell = true

the standard cell potential equals 0.67V = true ( 0.80 - 0.13 )

as the reaction proceeds, the concentration of the silver ions increases= false( silver ions decreases due to deposition)

the silver electrode is the anode = false(reduction occurs at silver electrode. so,it is cathode)