Question

Refer to this equation: 3 Cl2 + 6 KOH --> KCIO3 + 5 KCI + 3 H20 12.0 grams of Cl2 is reacted with excess KOH. If 8.70 g of KCl is obtained, what is the percent yield? Hint: find theoretical yield Hint: percent yield = (actual yield/ theoretical yield) x 100 O 62.1% O 51.4 % O 12.5 % O 87.1 % 41.3 % O 15.6 % O 89.0% 97.5%

Answer 1

• Answer is 41.3 %

Solution:

Theoretical yield:

(M.W. of Cl2= 70.906 g/mol, M.W. of KCl= 74.55 g/mol)

Here, 3 mole (3 x 70.906 g = 212.718 g) of Cl2 give 5 mole (5 x 74.55 g = 372.75 g) of KCl.

12 g of Cl2 react with excess of KOH, hence theoretical yield is calculate as below.

Theoretical yield = (372.75 x 12) / 212.718 = 21.02 g

Now, Percent yield = (actual yield/ theoretical yield) x 100

= (8.7 / 21.02) x 100

= 41.3 %