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15.32. Calculate the pH and pOH of the solutions with the following hydrogen ion or hydroxide ion concentrations. Indicate wh

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15.32 odwie LOH-3 : 1. 81 X GỒM (4 pOH = -logroh-) = 2.114 pH = 14-pH = 11.886 The solution is basic (b) [OH-] = 2.18 x 100M

Noce Note :- pH = -log [#₂0t] [the ot] [OH-] = 1x1014 pH + pH = 14 poH = -log [OH-] [hzot] = 10ph [OH-] = jo bom pH > 7 pH <7

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