Question

Nitrogen monoxide is produced by combustion in an automobile engine. According to the following reaction, how many moles of nitrogen dioxide will be formed upon the complete reaction of 29.4 grams of nitrogen monoxide with excess oxygen gas? nitrogen monoxide(g) + oxygen(g) nitrogen dioxide(g) moles nitrogen dioxide

Answer 1

Balancing equation is

2NO(g) + O2(g) + 2NO2(g)

molar mass of NO= 30 g/mol

Number of moles of NO in 29.4 g= mass of NO/Molar mass of NO

= 29.4 g/(30g/mol)

=29.4/30 mol

=0.98 mol

Now from the equation,we can write

2 mol of NO produced= 2 mol of NO2

=>1 mol of NO produced= 1 mol of NO2

=>0.98 mol of NO produced= 0.98 mol of NO2

Amount of NO2 formed= 0.98 mol