Question

A 0.0250 LL sample of a solution of Cu+(aq)Cu+(aq) requires 0.0328 LL of 0.132 molL−1molL−1 KMnO4(aq)KMnO4(aq) solution to reach the equivalence point. The products of the reaction are Cu2+Cu2+ and Mn2+.

What is the concentration of the resulting Cu2+(aq)Cu2+(aq) solution?

Answer 1

Mol. of KMnO4 = molasity * Vol 61 KMnOceat Girim urt" opere Mnoi tut Mnh caq, +62+ Youth Balance reaction in acidic medium in Mno cag.) + 5 Cut (aq.) +847 Cap.) → Mn2teq.) + 5 corte W +44,0 lume o ndon = 0.132 mol %0.0328 L . = 0.0043296 from balance reaction - imol of knnon react with 5 mol of cut 2-00433mol of knoy react with 0.091658 ml of cute. 0.004 3296 Mol of cot used 0.021648 mol 1. Volume of wt = 0.02504 0.021648 mol # Mol of a Mobinity of wat 0.0250L Ta volume cu i =0.86592 Dettem 5 mol of wt give 5 mol of cu++ 0.091648 Mol of cost give 0.02164 mol of wat = 0.021640 mil Total volum = 0.0328 L 701250L = 0.0578L Molarity of cutt _ 0.021646 mol . 00$781 -0.374 5M Molarity of cost = 0.375 m Answer