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5 2 points Calculate the (H)in a solution that has a pH of 4.11. Answer in scientific notation (ex: 1.0*10^-3) with two sign
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Answer #1

The given pH is 4.11

From the definition of pH-

pH = -log [H+]

4.11 = - log [H+]

log [H+] = -4.11

On Taking antilog we get-

[H+] = 7.8 × 10-5 mol/L.

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