The given pH is 4.11
From the definition of pH-
pH = -log [H+]
4.11 = - log [H+]
log [H+] = -4.11
On Taking antilog we get-
[H+] = 7.8 × 10-5 mol/L.
5 2 points Calculate the (H')in a solution that has a pH of 4.11. Answer in...
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