Question

im suppost to find the moles of H3po4 as well as Hcl but i cant figure out this equations that was given. i attached my data

pH vs. ml NaOH NOH Initial volume (ml) Final volume(ml) Difference(ml NaOH concentration (M) Initial volume of acid mixture First equiv point Second equiv, point 0.76 0.76 15.02 23.8 14.26 23.04 0.18 25 ml moles concentration Moles of NaOH used for reaching the 1st equiv. point: 2.5668 Moles of NaOH used for reaching the 2nd equiv. point 4.1472 Moles of H3PO4 HCI H3PO4

any chemistry please someone help, never said it was orhanic chemisty

Answer 1

The answer is attach below

is mixture of HC1 & ₂poy i Acid is mixture of the s - - -X4 19-24 22.0 20 2 SO 4o PO 0.76m2) vel. of Naon) Here first equivalont point = = 14.26 mi Calready remove Second equivalent point : x₂ = 213 u&me I Cabready rendel (Atter first equivalent point only topon. 8.16mb) is neutralize by base) Concentration of Hop e ginitialsreading of Nocu Catzeady) - éx, -, *abo) mi *0.1811 25 me Tirst 4 first & Second U second 25 S . equivalent point - [2x (ml)-23 24,156 = 3 x 0-4 3 WRONG FORMULA 25 m2 = 5.46 m2 YO•L8M 0.044 784 17 - 0337 2 Sime 1 1.1196 Mole of Har: (2X 1 - 7) mLX0-18m, = 0o m2 X 0.18m E mmol of HC) Y But this equation is wrong. due to at first e quaivalent point on the first HCl neutralize than after first equestsalent point, H3 POLL start reutralize. only

> Concentration of HCI - 0.76 mL) X 0.18 NI 25mL 14:26 mi treffit XO 1817 - 25 me Nole: 0-16 ML abready substructed 0.102672 M of HC = Concentraction = of HC mole of tic) = (x,-0.76m2) x 0.18 mel = 14.26 m2 80.18 mm) Mole of H = 2.5668 mmol fence this is correct Note: Mole of Hcl is equal do mole of Naoh. consume o this is correct HCl + Naon Na (+420 & E Concentration of ty poy = (15–2,) m2 *0.13 = (23.04 – 14-26)od x 0. de mol 255 25 not [M3 Por = 0.063216 Mol & mole of H₂ pon = (x2-x,) mL x 0.28 mol = 63-04-1420)ML x 0.38me! - 1.5804 numel = Mcle of Hapon = Male of Naoss 4.1472 - 7-56= 1580 u hemel Hence it is correct.
Note : In the titration of mixture of weak acid and strong acid first strong acid is neturalize always after first equivalent point than weak acid start neutralize

For strong acid your first equation is wrong