Question

4. In discussing the actinides, a standard reference text reads: There are a great many actinide nitrato complexes, many of which are important in the separation procedures whereby the elements are extracted from aqueous nitric acid into nonpolar solvents. Of these, the UO22+ complexes are the best characterized; they are typically eight-coordinate with two bidentate NO3ions and two neutral ligands (H20, THF, DMSO, and R3PO) forming a distorted equatorial hexagon. [DMSO is dimethylsulfoxide; R = alkyl or aryl. The two oxo ligands in UO2-* are trans. ] a. Show with a ChemDraw diagram how the nitrato ligand might bind bidentately (4 pts). b. What atom of a trialkylphosphine oxide is most likely to coordinate to any metal center? Apply VSEPR as necessary (4 pts). c. Based on this evidence, is UO22+ a hard or a soft acid? Justify your answer. What is the f- electron configuration of uranium in UO22*? (4 pts). d. What atom of dimethylsulfoxide is most likely to coordinate to uranium? Your answer should include a clear structure obtained from VSEPR, and rendered in ChemDraw. What is the geometry at sulfur? (6 pts)

Answer 1

The answer is attach below

Answer 4 @ The nitro ligand might bind bidenate by to u or . CD R R R p =0: according to VSEPR, only done pair bind to metal, because other remaing atom CR= alkylgrup) have no lone pais p electron do Oxygen has lone pair , sold Hence Oxygen "o" atom of a trialkylphosphine oxide ws most likely to coordinate to any metal center. i.e. M-OER 10 20 is a hard acid, due to u have to oxidation state, me to highen charge to radius rato, high oxidation state. ration: 15²25²26 35² 3p 3d to 45² 4 pt 4d 10 532 spt 4 f* 5420 65² opºsto Here Prelectronic configuration as 4814 & 5f0 10 116 (92) elect

Dimethylseelioride horide According to USGPR, Oxygen . has only lone pais election, Po o atom most likely to bind uranium UK:6=56 geometry of "s" atom in Now DMSO (Dimethyl sulfoxide) och 8.5 cm bsp2 hybridisation, hence trigonal planar geometry