Question

Based on your titration curves, determine the amount of sodium hydroxide added at the equivalence point in steps 3, 5, and 8. Use this information to calculate the total moles of acid that were neutralized in each of the titrations.

26.0mL NaOH, 0.5 M HCl 0.5M NaOH

1.0mL NaOH, 0.5 M CH₃CO₂H 0.5M NaOH

50.0mL NaOH, 1.0 M CH₃CO₂H 0.5M NaOH

HCl + NaOH -> H₂O + NaCl

CH₃CO₂H + NaOH -> NaC₂H₃O₂ + H₂O

Answer 1

Answer (1) 26.0 ml NaOH ; 0.5 M NaOH ; 0.5M HU 1000 HCl & NaOH H2O + NaCl Mahot, Amount of NaOH used = Molarity & Volume (L). = 0.5 X 26 nNaOH = 0.013 moles! Applying Formula - Nivi = N2 V2 ( h. MiVi = R2M2 Vz) (HU) (NaOH) n-factor 1x 0.5 x V = 0.5 X 26-0 X1 [= 26.0 mL/ oles of He neutralized = Molasity of HQ x Volume (1) (nuce) = 0.5 x 26 1000 Inace = 0.013 moles] (2) 1.0 ml NaOH ; 0.5M CH3COOH ; 0.5M NAOH CH3COOH + NaOH - CH₃COONa + H2O Nach, Amount of NaOH used = Molarity of NaOH X Volume (4) = 0.5 x L 1000 nNaOH = 0.0005 moles) Applying Formula - Nivi = N2 V2 (CH3COOH) (NaOH) - Nimivi = N2 M2 V2 => 1X0.5 x V, = 1X0.5 X ! - [Vi= 1 mL

Moles of Charool neutralized = Molarity of Chacool X Volume (L) (nenacoon) = 0.5% norscoot = 0.0005 moles, 1060 (2) Custoot (3) 50.0 mL NaOH ; 1.0M CH3COOH ; 0.5M NaOH CH3COOH + NaOH CH3COONa + H₂O Noor, Amount of NaOH used = Molarity & Volume (1) = 0.5 X 50 1000 Nach = 0.025 moles] Applying formula - Nivi = Nava (CH3cook) (NaOH) - nimiv = 12 M2 V2 => 18 1 XVI = 180.5 x 50 - [V, = 25 ml Moles of CH3COOH neutralized = (M CH3COOH) = Molarity of CH3 COOH x Volume (2) used (2) I x 25 1ooo Menscout = 0.025 moles /