Calculate the standard cell potential (∆Eo) for the galvanic cell:

from data table:
Eo(Ni2+/Ni(s)) = -0.23 V
Eo(Ag+/Ag(s)) = 0.79 V
As per given cell notation,
cathode is (Ag+/Ag(s))
anode is (Ni2+/Ni(s))
Eocell = Eocathode - Eoanode
= (0.79) - (-0.23)
= 1.02 V
Answer: 1.02 V
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