Question

CWIII-101 BRI —7.567 —7.527 7.327 7.323 ER 7.164 27.160 7.144 7.139 6.832 26.812 6.780 6.740 — 6.055 CWIII-101 NAME EXPNO PROCNO Date Time INSTRUM PROBHD PULPROG 20100305 20.22 spect 5 mm PABBO BB- zg30 65536 DMSO Тр SOLVENT NS DS SWH FIDRES AO RG 8223.685 HZ 0.125483 HZ 3.9846387 sec DW DE TE 60.800 usec 6.50 sec 293.0 K 1.00000000 sec D1 TDO P1 ======== CHANNEL f1 ======== NUCI 1H 10.00 usec PL1 -1.80 dB PL1W 21.67079544 W SF01 400.1324710 MHZ SI 32768 SE 400.1300046 MHZ WDW EM SSB LB 0.30 Hz 1.00 7.7 7.6 7.5 7.4 7.3 7.2 7.1 7.0 6.9 6.8 6.7 6.6 6.5 6.4 6.3 6.2 6.1 6.0 ppm

Label CNMR &HNMR CURCUMIN on the spectrums

Answer 1

The skuchure of Curcumon is as follows urcumin obot a 4 OH H ochy dowy H-NMR speckum There are 8 types of persons tut (1) two singlets at 7.567 8 7.527 for at are due to a ? (10) doubled and 7.327-7.323 ppm for at iy due to "d" (1) doublet & ad 7.164 – 7:39 fr QH is due he (10) @ Two douldets b/w 6.822 -6.740 are due "C" and "e" respefully. (1) A singles at 6.055 ppen is due to offer 1H (VI) A singles around 4 ppm fes Octly is missing in the speckim, which should also be present

BC - NMR speekam There are elever peaks in the spection Ho se I h i J 6 U OH (1) A peak arauf 183.23 is due to 'i ( Carbonyl Carbon) (11) A peak at 1498 148 are due "a" & "fr respectively. (1) A peak at 55.70 is due to "K" (ochy) . (10) A peak at 10.89 is due to 'J (U) A peak at lll $115 are due to b and e respectuly (1) A perk at 140 ppm is due to 8 Cup A peak at 126 and 123 are due to "l' and 'd"resp (v) a peak at 121.10 ppm is due to h NOTE 8 AD CAMERA