Question

5.) Give the condensed formulas of the products using Markovnikov's Rule as needed CH₃ CH₃-C =CH-CH₃ + HCl b.) CH₃ -CH ₂ -CH=CH-CH-CH₂ + H₂O c) C + (Hi-C = CH HBr - CH e) (H₂-CH=CH-CH₂ Ch . CO CH3-C=CH-CH-CH₃ + He

Answer 1

The condensed molecular formula for the products are given below in the following picture,

Markonikov's rule:

when the addition of the haloacids to the asymmetric alkene the hydrogen gets attached to the carbon containing more hydrogen atoms and the halide is attached to the carbon containing more alkyl substituents,

CH; -C = CH – CHin + HCl cus t db. 11) : 1) . 110 CH, * ? CH, -CHE cl (o) CHg - CH - CH = CH - CH - CH H o | 1+ ip CH, - CH, - CH, - CH=CH-CH3 애 | (c) CH, 10 .. . + HBrt. 대, ~ C = H - CH - CHa

CH3 CH₃ Но А Я, (2) (2) CH3 – CH = CH – CH3 + clz CH3 - CH - CH - CH3 . . . c. cг Е, с/ ң, - сн. - t = cң – ен , - сня + Hс! - - - - - al no са» — с - СН – Сң - СНА Н . cl : .