molarity of H2S = no of moles/volume in L
= 0.125/0.45 = 0.277moles
---------2H2S(g)----------------> 2H2(g) + S2(g)
I---------- 0.277 -------------------0 ------------0
C-------- -2x ---------------------- 2x ---------- x
E------ 0.277-2x ---------------- 2x ---------- x
Kc = [H2]^2[S2]/[H2S]^2
1.67*10^-7 = (2x)^2*x/(0.277-2x)^2
1.67*10^-7(0.277-2x)^2 = 4x^3
x = 0.00146
[H2S] = 0.277-2x = 0.277-2*0.00146 = 0.27408M
[H2] = 2x = 2*0.00146 = 0.00292M
[S2] = x = 0.00146M
uten TUHUM16 Celes. Tali YUU!! Given the reaction below: 2 H2S(8) « 2H26€) + S2(8) Kc...
Consider the reaction for the decomposition of H2S: 2H2 (g) --> 2H2 (g) + S2 (g) <-- Kc= 1.67 x 10^-7 at 800 degrees Celsius H 0.5 L reaction vessel initially contains 0.0125 mol of H2S at 800 degrees Celsius find the equilibrium concentrations of H2 and S2
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