Question

Calculate the final temperature of 6.84 g of praseodymium (specific heat capacity = 0.193 J g-1...

Calculate the final temperature of 6.84 g of praseodymium (specific heat capacity = 0.193 J g-1 °C-1) initially at 26.8 °C that releases 11.3 J of energy into the surroundings.

A)14.3°C

B)18.2 °C

C)21.6 °C

D)23.8 °C

E)8.17 °C

0 0
Add a comment Improve this question Transcribed image text
Answer #1

solution: we know that o=m.c.oT where Q= amount of heat releases/absorbed m= mass of substante C= specific heal capacity OT =

Add a comment
Know the answer?
Add Answer to:
Calculate the final temperature of 6.84 g of praseodymium (specific heat capacity = 0.193 J g-1...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Calculate the final temperature of 68.4 g of molecular hydrogen (specific heat capacity = 14.304 J...

    Calculate the final temperature of 68.4 g of molecular hydrogen (specific heat capacity = 14.304 J g-1 °C-1) initially at 8.24 °C that releases 25.3 kJ of energy into the surroundings.

  • A 7.00-g sample of aluminum pellets (specific heat capacity = 0.89 J/°C·g) and a 14.00-g sample...

    A 7.00-g sample of aluminum pellets (specific heat capacity = 0.89 J/°C·g) and a 14.00-g sample of iron pellets (specific heat capacity = 0.45 J/°C·g) are heated to 100.0 °C. The mixture of hot iron and aluminum is then dropped into 71.3 g water at 22.0 °C. Calculate the final temperature of the metal and water mixture, assuming no heat loss to the surroundings.

  • A 3.00-g sample of aluminum pellets (specific heat capacity = 0.89 J/°C·g) and a 11.00-g sample...

    A 3.00-g sample of aluminum pellets (specific heat capacity = 0.89 J/°C·g) and a 11.00-g sample of iron pellets (specific heat capacity = 0.45 J/°C·g) are heated to 100.0 °C. The mixture of hot iron and aluminum is then dropped into 73.8 g water at 22.0 °C. Calculate the final temperature of the metal and water mixture, assuming no heat loss to the surroundings. Please be super specific on how you get to each step!

  • A 3.00-g sample of aluminum pellets (specific heat capacity=0.89 J/°C g) and a 18.50-g sample of...

    A 3.00-g sample of aluminum pellets (specific heat capacity=0.89 J/°C g) and a 18.50-g sample of iron pellets (specific heat capacity = 0.45 J/°C-g) are heated to 100.0 °C. The mixture of hot iron and aluminum is then dropped into 77.4 g water at 22.0 °C. Calculate the final temperature of the metal and water mixture, assuming no heat loss to the surroundings. Final temperature = 20.23 °C An error has been detected in your answer. Check for typos. miscalculations...

  • The specific heat capacity of silver is 0.24 J/°C .g. (a) Calculate the energy required to...

    The specific heat capacity of silver is 0.24 J/°C .g. (a) Calculate the energy required to raise the temperature of 140.0 g Ag from 273 K to 305 K. (b) Calculate the energy required to raise the temperature of 1.0 mol Ag by 1.0°C (called the molar heat capacity of silver). O J/mol°C (c) It takes 1.35 kJ of energy to heat a sample of pure silver from 12.0°C to 15.3°C. Calculate the mass of the sample of silver. 9

  • Specific Heat Capacity A 21.5-g sample of an unknown metal is heated to 94.0°C and is...

    Specific Heat Capacity A 21.5-g sample of an unknown metal is heated to 94.0°C and is placed in a insulated container containing 128 g of water at a temperature of 21.4°C. After the metal cools, the final temperature of the metal and water is 25.0°C. Calculate the specific heat capacity of the metal, assuming that no heat escapes to the surroundings. Heat loss=Heat gained. Specific Heat Capacity of water is 4.18 J/g/K in this temperature range. Submit Answer Incompatible units....

  • 2 point(s) Specific Heat Capacity The specific heat capacity of lead at 25°C is 1.290x10-1 J/g/K....

    2 point(s) Specific Heat Capacity The specific heat capacity of lead at 25°C is 1.290x10-1 J/g/K. For a 3.00x 102 g sample of lead, how much will the temperature increase if 3.096x102 ) of energy is put into the system? (Assume that the heat capacity is constant over this temperature range.) 1pts Submit Answer Tries 0/5 What is the molar heat capacity of lead? 1 pts Submit Answer Tries 0/5 e Post Discussion

  • 6.21) Is the specific heat capacity of a substance an intensive or extensive property? Explain. 6.23) Calculate q when 0...

    6.21) Is the specific heat capacity of a substance an intensive or extensive property? Explain. 6.23) Calculate q when 0.10 g of ice is cooled from 10. °C to -75. °C. (S ice = 2.087 J/g•°C). 6.25) A 27.7 g sample of ethylene glycol, a car radiator coolant, loses 688 J of heat. What was the initial temperature of the ethylene glycol if the final temperature is 32.5 °C? (s of ethylene glycol = 2.42 J/g•°C) 6.27) One piece of...

  • A 21.0 g sample of aluminum, which has a specific heat capacity of 0.897 J g...

    A 21.0 g sample of aluminum, which has a specific heat capacity of 0.897 J g '°C ', is dropped into an insulated container containing 200.0 g of water at 25.0 °C and a constant pressure of 1 atm. The initial temperature of the aluminum is 90.1 °C Assuming no heat is absorbed from or by the container, or the surroundings, calculate the equilibrium temperature of the water. Be sure your answer has 3 significant digits. x10 ? X

  • the specific heat of a certain type of metal is 0.128 J/(g C). What is the final temperature if 305 J of heat is added t...

    the specific heat of a certain type of metal is 0.128 J/(g C). What is the final temperature if 305 J of heat is added to 39.3 g of this metal, initially at 20.0 C?

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT